Use descartes' rule of signs to determine the possible numbers of positive and negative real zeros of f (x )equals x cubed plus 5 x squared plus 7 x plus 6f(x)=x3+5x2+7x+6. what are the possible numbers of positive real zeros?

  0

Step-by-step explanation:

All of the terms have positive signs, so there are no sign changes. Zero sign changes means there are zero positive real roots.

77, 78 and 79

Step-by-step explanation:

Let the three consecutive nos be x, x+1, x+2

From the question, x+x+1+x+2=234

3x+3=234

3x=231

x=77

The consecutive numbers are 77,78,79