(x^2+3x-7)(2x-5) write in standard form

Hi there!
The question is asking us to simplify the expression (x² + 3x - 7)(2x - 5) and write the answer in standard form. Here is how you do that - 
Original: (x² + 3x - 7)(2x - 5)
Break it apart - [(x² + 3x - 7)(2x)] + [(x² + 3x - 7)(-5)]
Simplify - 
2x³ + 6x² - 14x - 5x² - 15x + 35
Now, combine like terms - 
2x³ + x² - 29x + 35
Therefore, the answer to your query is 2x³ + x² - 29x + 35. Hope this helps!

Ok,

The total is 64$:

= 64

It shows us one of the numbers for the equation, 13

+ 12 = 63

Two passes together plus the thirteen equals the total of 63$

the price of the pass is unknown, so we can use a variable to figure it out:

2x + 12 = 64

Now we solve

First subtract 12 from both sides:

2x + 12 - 12 = 64 - 12

Then divide both sides by 2:

2x ÷ 2 = 52 ÷ 2

And now we have our

x = 26