Physics: A ball is thrown in the air at an angle of 60.0° to the ground, with an initial speed of 30m/s. How far from its original position does it land?

A ball is thrown in the air at an angle of 60.0°

linreaburg

11.02.2022

The distance is $R = 79.5 \ m$

Explanation:

From the question we are told that

The angle at which the ball is thrown is $\theta = 60^o$

The initial speed is $u = 30 \ m/s$

Generally the distance from the original position which the ball covered is mathematically evaluated as

$R = \frac{ u^2 * sin 2\theta }{g}$

=> $R = \frac{ 30^2 * sin (2* 60)}{9.8}$

=> $R = 79.5 \ m$

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