kristalmakhija
13.06.2020 •
Physics
A hook of radius 2m weighs 100kg. It rolls along a horizontal floor so that its centre if mass has a speed of 20cm/s. How much work has to be done to stop it?
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Ответ:
2 J
Explanation:
Work = change in energy
W = ΔKE
W = ½ mv²
W = ½ (100 kg) (0.2 m/s)²
W = 2 J
Ответ:
4Nm
Explanation:
Work done is force times distance.
The force is given as mass x (speed )^2 / raduis . Expressed mathematically we have ;
Mv^2/r
Then for the slightest measurable distance r we have: the work done as;
Mv^2/r × r
= Mv^2
= 100 × 0.2 × 0.2= 4Nm
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