Physics: A mass of 2.5kg is attached to a spring and the system is undergoing simple harmonic osciallyions with the frequncys of 3.0 Hz and an amplitude of 8.25 cm. What is the total mechanical enegry of the system?

A mass of 2.5kg is attached to a spring and the

pattydixon6

18.01.2022

E=36.64J

Explanation:

The total mechanical energy of a mass-spring system is defined as:

$E=\frac{kA^2}{2}$

Here k is the spring constant and A is the amplitude of the oscillations.

We can calculate the spring constant using the natural frequency of this system:

$\omega^2=\frac{k}{m}\\k=m\omega^2$

Recall that $\omega=2\pi f$ , so:

$k=m(2\pi f)^2\\k=2.5kg(2\pi*3Hz)^2\\k=888.26\frac{N}{m}$

Finally, we calculate E:

$E=\frac{888.26\frac{N}{m}(8.25*10^-2m)^2}{2}\\E=36.64J$

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leeorareeves299

14.11.2022

Explanation:

Edge 2020

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