lavishbre12
13.05.2021 •
Physics
A student uses a spring to launch a marble vertically in the air. The mass of the marble is
0.02 kg and when the spring is stretched 0.08 m it exerts a force of 58 N. What is
the maximum height the marble can reach?
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Ответ:
the maximum height reached by the marble is 11.84 m.
Explanation:
Given;
mass of the marble, m = 0.02 kg
extension of the string, x = 0.08 m
force applied to the string, F = 58 N
Apply the principle of conservation of energy;
elastic potential energy = gravitational potential energy
¹/₂fx = mgh
Therefore, the maximum height reached by the marble is 11.84 m.
Ответ: