Physics: A0.145 kg baseball pitched at 35.0 m/s is hit on a horizontal line drive straight back at the pitcher at 56.0 m/s. if the contact time between the bat and ball is 5.00 × 10−3 calculate the force (assumed to be constant) between the ball and bat.

ya Explanation: i hope nobody get coronavirus at school that would be terrible hope it fun!...

A0.145 kg baseball pitched at 35.0 m/s is hit on - id01453504954508, deidaralove90

smiley0326

17.01.2022

2639 N

Explanation:

The impulse on the baseball is given by:

$I=F \Delta t$ (1)

where F is the force exerted on the ball and $\Delta t$ the contact time between the bat and the ball.

The impulse is also equal to the change in momentum of the ball:

$I=\Delta p = m (v-u)$ (2)

where m is the ball's mass, v is its final velocity, u is its initial velocity.

By using (1) and (2) simultaneously we can write an expression for F, the force exerted on the ball:

$F=\frac{m(v-u)}{\Delta t}$

where:

m = 0.145 kg

u = 35.0 m/s

v = -56.0 m/s

$\Delta t=5.00 \cdot 10^{-3}s$

Substituting,

$F=\frac{(0.145 kg)((-56.0 m/s)-35.0 m/s)}{5.00\cdot 10^{-3} s}=-2639 N$

and the negative sign means that the force is simply in the opposite direction to the ball's initial direction.

0,0(0 оценок)