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jakhunter354
27.11.2019 •
Physics
A36.9-kg crate rests on a horizontal floor, and a 64.9-kg person is standing on the crate. determine the magnitude of the normal force that (a) the floor exerts on the crate and (b) the crate exerts on the person.
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Ответ:
FN = 997.64 N :Force that the floor exerts on the crate
Fcp = 636.02N, vertical and upaward
Explanation:
Wp: person Weigth (N)
Wc: crate Weigth ( N)
FN: Normal force
Calculated of the weight
Wc=(36.9kg)(9.8 m/s²) = 361.62 N
Wp= (64.9kg)(9.8 m/s²) = 636.02N
(a) Force that the floor exerts on the crate
For free body diagram of the crate+person
∑Fy=0
FN-Wc-Wp = 0
FN-361.62 N-636.02N= 0
FN = 997.64 N :Force that the floor exerts on the crate
(b) For free body diagram of the crate
Fpc: Force of the person on the box
∑Fy=0
FN-Wc-Fpc = 0
997.64 N-361.62 N = Fpc
Fpc =636.02N :Force of the person on the crate(vertical and downaward)
Newton's third law or principle of action and reaction :
Force of the person on the crate = - Force of the crate on the person
Fpc = - Fcp
Fcp:Force of the crate on the person
Fcp = 636.02N, vertical and upaward
Ответ: