Ametal ball of specific heat capacity 400 joule per kgper celsius is allowed to fall from a height of 100 metre .if the ball on hitting the ground stops and all the energy possessed by it is converted into heat energy calculate the rise in temperature of the ball (g = 200 metre per second square)
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Ответ:
G.P.E = mgh = 0.2 * 10 * 100 = 200 J
Now we'll calculate the temperature rise
Q = m * c * (t2 - t1)
Q/(m * c) = t2-t1
t2 = Q/(m * c) + t1 = 200/(0.2 * 400) + 0 = 2.5 C
Ответ:
heat to mechanical to electrical
Explanation: