Physics: Atank holds 10.3 mol of an ideal gas at an absolute pressure of 519 kpa while at a temperature of 361.38°c. (a) compute the container s volume (b) the gas is now heated to 651.6 °c. what is the pressure of the gas now?

75 cm³Explanation:The volume of a substance when given the density and mass can be found by using the formulaFrom the question we haveWe have the final answer as75 cm³Hope this helps you...

Atank holds 10.3 mol of an ideal gas at an absolute

Ответ:

jayzelgaspar8005

02.01.2022

Physics

(a) 62.57 L

(b) 801.94 kPa

Explanation:

Given:

= number of moles of gas = 10.3 mol

P_1 = initial pressure of the gas = $519\ kPa = 5.19\times 10^5\ Pa$

T_1 = initial temperature of the gas = $361.38^\circ C = (361.38+273)\K = 598.38\ K$

T_2 = final temperature of the gas = $651.6^\circ C = (651.6+273)\K = 924.6\ K$

= volume of the tank

R = universal gas constant = 8.314 J/mol K

Part (a):

Using Ideal gas equation, we have

$PV=nRT\\\Rightarrow V = \dfrac{nRT}{P}\\\Rightarrow V = \dfrac{10.3\times 8.314\times 598.38}{5.19\times 10^{5}}\\\Rightarrow V = 6.2567\times10^{-2}\ m^3\\\Rightarrow V = 62.567\ L$

Hence, the volume of the container is 62.567 L.

Part (b):

As the volume of the container remains constant.

Again using ideal gas equation,

$PV=nRT\\\because V,\ n, R\ are\ constant\\\therefore \dfrac{P_1}{P_2}=\dfrac{T_1}{T_2}\\\Rightarrow P_2 = \dfrac{T_2}{T_1}P_1\\\Rightarrow P_2 = \dfrac{924.6}{598.38}\times 519\\\Rightarrow P_2 = 801.94\ kPa$