Will mark brainliest! the driver of a pickup truck going 120 km/h applies the brakes, giving the truck a uniform deceleration of 5.00 m/s^2, while it travels 35.0 m. how much time has elapsed?

First put the speed in m/s.  120km/h = 33.33m/s.  Now the position function is the integral of velocity, and velocity is in turn the integral of acceleration.  The velocity is:

Now we integrate this expression to get the position. The constant of integration will be the distance the truck travels.

Here we set the distance, 35m as negative because I assumed the stopping point of the truck is the origin.  Putting t=0 shows it starts at -35m. 
Now solve the following equation for the time, t using the quadratic equation:

and choose the  value t=1.149s

Explanation:

Given that:

A tugboat tows a ship with a constant force of magnitude F1 and then increases the ship's speed during a 10 s interval with 2.0 km/h.

If  F = ma

we can say for

where :

      since F is constant so ; acceleration too is constant

= 2.0 km/h

=

= 0.556 m/s

 

Similarly ;

We can as well say ;

= 3.0556 m/s²

Now; the additional force acting on the ship in the same direction of the force  i.e the net force is :

Thus; we can say:

Thus, the magnitude of F1 and F2 compare in a way that says: