What is the mass of a sample of glucose (c6h12o6), in kg, if there are 2.75x10^25 molecules present?
respond with the correct number of significant figures in scientific notation (use e notation and only 1 digit before decimal e.g. 2.5e5 for 2.5 x 10⁵)

8.22E⁰ kg

Explanation:

Given data:

Mass of glucose = ?

Number of molecules = 2.75×10²⁵ molecules

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 2.75×10²⁵ molecules of glucose:

One mole of glucose = 180 g

180 g/6.022 × 10²³ molecules× 2.75×10²⁵ molecules

82.2 × 10² g

8220 g

8.22 Kg

8.22E⁰ kg

Since the molecular weight of water is about 18 g/mol, you have about 1 mol of water. So, now we know that it takes approximately 46.2 kJ of heat energy to warm 18.02g of water from 25C to 100C and then to vaporize it into steam. Hopefully this helped!

Explanation: