A particle is accelerated uniformly from rest to a speed of 50 meters per second in 5.0 seconds. The adverse speed of the particle during this 5.o-second time interval is ?
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Ответ:
The magnification is 1, that is the image is upright and the same size as the object
The location of the image is behind the mirror (virtual image)
Explanation:
Here we have the mirror equation presented as follows;
Where:
R = Radius of curvature of the mirror = 40.0 cm
f = Focal length of the mirror = 1/2 × R = 1/2 × 40 = 20 cm
m = Magnification of the mirror
Plugging in the values, we have
∴
= -10 cm which means a virtual image, behind the mirror
The magnification is found and presented as follows;
Therefore, the image is upright and the same size as the object.